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Permutations and Combinations: Formulas, Shortcuts and Solved Examples — MCQs with Answers (Set 5)

This lesson gives each rule, the reason it works and seven worked examples. It also lists the traps that cost marks.

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Q1. Evaluate 4P3.

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Answer: D

We need 4P3, permutations of 4 items taken 3 at a time. We’re arranging 3 items out of 4, where order matters, so we use permutations. nPr = n! / (n-r)!, so 4P3 = 4! / 1!. This is the product of 3 numbers counting down from 4: 4 x 3 x 2 = 24. So 4P3 = 24.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

Q2. Evaluate 9P4.

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Answer: C

We need 9P4, permutations of 9 items taken 4 at a time. We’re arranging 4 items out of 9, where order matters, so we use permutations. nPr = n! / (n-r)!, so 9P4 = 9! / 5!. This is the product of 4 numbers counting down from 9: 9 x 8 x 7 x 6 = 3024. So 9P4 = 3024.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

Q3. Evaluate 8P4.

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Answer: B

We need 8P4, permutations of 8 items taken 4 at a time. We’re arranging 4 items out of 8, where order matters, so we use permutations. nPr = n! / (n-r)!, so 8P4 = 8! / 4!. This is the product of 4 numbers counting down from 8: 8 x 7 x 6 x 5 = 1680. So 8P4 = 1680.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

Q4. Evaluate 11P3.

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Answer: D

We need 11P3, permutations of 11 items taken 3 at a time. We’re arranging 3 items out of 11, where order matters, so we use permutations. nPr = n! / (n-r)!, so 11P3 = 11! / 8!. This is the product of 3 numbers counting down from 11: 11 x 10 x 9 = 990. So 11P3 = 990.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

Q5. Evaluate 7P4.

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Answer: A

We need 7P4, permutations of 7 items taken 4 at a time. We’re arranging 4 items out of 7, where order matters, so we use permutations. nPr = n! / (n-r)!, so 7P4 = 7! / 3!. This is the product of 4 numbers counting down from 7: 7 x 6 x 5 x 4 = 840. So 7P4 = 840.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

Q6. Evaluate 13P3.

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Answer: D

We need 13P3, permutations of 13 items taken 3 at a time. We’re arranging 3 items out of 13, where order matters, so we use permutations. nPr = n! / (n-r)!, so 13P3 = 13! / 10!. This is the product of 3 numbers counting down from 13: 13 x 12 x 11 = 1716. So 13P3 = 1716.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

Q9. Evaluate 10!

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Answer: B

We need 10 factorial, written 10!. 10! means multiply every whole number from 10 down to 1. 10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 3628800. So the answer is 3628800.

Related topics: Permutations and Combinations: Formulas, Shortcuts and Solved Examples

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