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Q1. The sum of the ages of Anita, Rohan, and Divya is 99 years. If Anita is 10 years older than Divya, and the total of Rohan and Divya’s ages is 62 years, what is Rohan’s age?
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Answer: A
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 99. Fact 2: A is 10 years older than D, so A – D = 10. Fact 3: R + D = 62. From facts 1 and 3: A = 99 – 62 = 37. From fact 2: D = A – 10 = 37 – 10 = 27. From fact 3: R = 62 – D = 62 – 27 = 35. Check: A + R + D = 37 + 35 + 27 = 99, confirming the answer. So Rohan’s age is 35.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q2. In a ratio-based age problem, if a person’s present age is r times a common multiplier x, and n years pass, their new age is expressed as what?
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Answer: C
The present age is rx, built from ratio multiplier r and variable x. After n years pass, every person’s age increases by exactly n. This n is a fixed number of years, added once, not multiplied. So the new age is rx + n, with n added directly. It is not r(x+n), which would wrongly multiply n by r too. For example, if r=3, x=5, n=2: the age is 3(5)+2 = 17, not 3(5+2) = 21.
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Q3. In age-ratio word problems, when a ratio r1:r2 changes to r3:r4 after n years, the standard approach is to do what?
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Answer: D
Represent both present ages using one variable x. Let the ages be r1x and r2x, based on the given ratio. After n years, each age increases by exactly n. So the ages become r1x + n and r2x + n. Set this equal to the new ratio: (r1x + n)/(r2x + n) = r3/r4. Cross-multiply, then collect the x terms on one side. Solving this equation gives the value of x directly.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q4. Consider this data-sufficiency question: what is B’s present age? Statement I: A is 6 years older than B. Statement II: the total of B and C’s ages is 40 years. Which of these is correct?
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Answer: B
Statement I alone gives a relationship between A and B only, not B’s actual age. Statement II alone gives a relationship between B and C only, not B’s actual age either. Together, Statement I says A – B = 6, and Statement II says B + C = 40. That is two equations, but three unknowns: A, B, and C. This system cannot be solved for B’s specific value. So both statements together are still not sufficient.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q5. The average of the ages of Karan and Sophie is 12 years. If the respective ratio of their ages 5 years from now is 23:11, what is Sophie’s present age (the smaller ratio value)?
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Answer: C
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 12, so A + B = 2 x 12 = 24. Fact 2: 5 years from now, their ages are in the ratio 23:11. So let their future ages be 23y and 11y, for some number y. Fact 3: present age plus 5 equals future age, so A = 23y – 5 and B = 11y – 5. Substituting into fact 1: (23y – 5) + (11y – 5) = 24. This simplifies to 34y – 10 = 24, so y = 1. So B = 11 x 1 – 5 = 6. Check: A = 23 x 1 – 5 = 18, and A + B = 18 + 6 = 24, confirming the answer. So Sophie’s present age is 6.
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Q6. The average of the ages of Karan and Sophie is 63 years. If the respective ratio of their ages 6 years from now is 97:41, what is Sophie’s present age (the smaller ratio value)?
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Answer: B
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 63, so A + B = 2 x 63 = 126. Fact 2: 6 years from now, their ages are in the ratio 97:41. So let their future ages be 97y and 41y, for some number y. Fact 3: present age plus 6 equals future age, so A = 97y – 6 and B = 41y – 6. Substituting into fact 1: (97y – 6) + (41y – 6) = 126. This simplifies to 138y – 12 = 126, so y = 1. So B = 41 x 1 – 6 = 35. Check: A = 97 x 1 – 6 = 91, and A + B = 91 + 35 = 126, confirming the answer. So Sophie’s present age is 35.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q7. The average of the ages of Karan and Sophie is 28 years. If the respective ratio of their ages 5 years from now is 15:7, what is Sophie’s present age (the smaller ratio value)?
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Answer: A
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 28, so A + B = 2 x 28 = 56. Fact 2: 5 years from now, their ages are in the ratio 15:7. So let their future ages be 15y and 7y, for some number y. Fact 3: present age plus 5 equals future age, so A = 15y – 5 and B = 7y – 5. Substituting into fact 1: (15y – 5) + (7y – 5) = 56. This simplifies to 22y – 10 = 56, so y = 3. So B = 7 x 3 – 5 = 16. Check: A = 15 x 3 – 5 = 40, and A + B = 40 + 16 = 56, confirming the answer. So Sophie’s present age is 16.
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Q8. The average of the ages of Karan and Sophie is 16 years. If the respective ratio of their ages 3 years from now is 23:15, what is Sophie’s present age (the smaller ratio value)?
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Answer: D
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 16, so A + B = 2 x 16 = 32. Fact 2: 3 years from now, their ages are in the ratio 23:15. So let their future ages be 23y and 15y, for some number y. Fact 3: present age plus 3 equals future age, so A = 23y – 3 and B = 15y – 3. Substituting into fact 1: (23y – 3) + (15y – 3) = 32. This simplifies to 38y – 6 = 32, so y = 1. So B = 15 x 1 – 3 = 12. Check: A = 23 x 1 – 3 = 20, and A + B = 20 + 12 = 32, confirming the answer. So Sophie’s present age is 12.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q9. The average of the ages of Karan and Sophie is 28 years. If the respective ratio of their ages 6 years from now is 41:27, what is Sophie’s present age (the smaller ratio value)?
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Answer: A
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 28, so A + B = 2 x 28 = 56. Fact 2: 6 years from now, their ages are in the ratio 41:27. So let their future ages be 41y and 27y, for some number y. Fact 3: present age plus 6 equals future age, so A = 41y – 6 and B = 27y – 6. Substituting into fact 1: (41y – 6) + (27y – 6) = 56. This simplifies to 68y – 12 = 56, so y = 1. So B = 27 x 1 – 6 = 21. Check: A = 41 x 1 – 6 = 35, and A + B = 35 + 21 = 56, confirming the answer. So Sophie’s present age is 21.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q10. The average of the ages of Karan and Sophie is 13 years. If the respective ratio of their ages 4 years from now is 9:8, what is Sophie’s present age (the smaller ratio value)?
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Answer: B
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 13, so A + B = 2 x 13 = 26. Fact 2: 4 years from now, their ages are in the ratio 9:8. So let their future ages be 9y and 8y, for some number y. Fact 3: present age plus 4 equals future age, so A = 9y – 4 and B = 8y – 4. Substituting into fact 1: (9y – 4) + (8y – 4) = 26. This simplifies to 17y – 8 = 26, so y = 2. So B = 8 x 2 – 4 = 12. Check: A = 9 x 2 – 4 = 14, and A + B = 14 + 12 = 26, confirming the answer. So Sophie’s present age is 12.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q11. The average of the ages of Karan and Sophie is 27 years. If the respective ratio of their ages 6 years from now is 17:16, what is Sophie’s present age (the smaller ratio value)?
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Answer: D
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 27, so A + B = 2 x 27 = 54. Fact 2: 6 years from now, their ages are in the ratio 17:16. So let their future ages be 17y and 16y, for some number y. Fact 3: present age plus 6 equals future age, so A = 17y – 6 and B = 16y – 6. Substituting into fact 1: (17y – 6) + (16y – 6) = 54. This simplifies to 33y – 12 = 54, so y = 2. So B = 16 x 2 – 6 = 26. Check: A = 17 x 2 – 6 = 28, and A + B = 28 + 26 = 54, confirming the answer. So Sophie’s present age is 26.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q12. The average of the ages of Karan and Sophie is 33 years. If the respective ratio of their ages 5 years from now is 47:29, what is Sophie’s present age (the smaller ratio value)?
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Answer: C
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 33, so A + B = 2 x 33 = 66. Fact 2: 5 years from now, their ages are in the ratio 47:29. So let their future ages be 47y and 29y, for some number y. Fact 3: present age plus 5 equals future age, so A = 47y – 5 and B = 29y – 5. Substituting into fact 1: (47y – 5) + (29y – 5) = 66. This simplifies to 76y – 10 = 66, so y = 1. So B = 29 x 1 – 5 = 24. Check: A = 47 x 1 – 5 = 42, and A + B = 42 + 24 = 66, confirming the answer. So Sophie’s present age is 24.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q13. The average of the ages of Karan and Sophie is 21 years. If the respective ratio of their ages 6 years from now is 5:4, what is Sophie’s present age (the smaller ratio value)?
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Answer: D
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 21, so A + B = 2 x 21 = 42. Fact 2: 6 years from now, their ages are in the ratio 5:4. So let their future ages be 5y and 4y, for some number y. Fact 3: present age plus 6 equals future age, so A = 5y – 6 and B = 4y – 6. Substituting into fact 1: (5y – 6) + (4y – 6) = 42. This simplifies to 9y – 12 = 42, so y = 6. So B = 4 x 6 – 6 = 18. Check: A = 5 x 6 – 6 = 24, and A + B = 24 + 18 = 42, confirming the answer. So Sophie’s present age is 18.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q14. The average of the ages of Karan and Sophie is 9 years. If the respective ratio of their ages 3 years from now is 5:3, what is Sophie’s present age (the smaller ratio value)?
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Answer: A
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 9, so A + B = 2 x 9 = 18. Fact 2: 3 years from now, their ages are in the ratio 5:3. So let their future ages be 5y and 3y, for some number y. Fact 3: present age plus 3 equals future age, so A = 5y – 3 and B = 3y – 3. Substituting into fact 1: (5y – 3) + (3y – 3) = 18. This simplifies to 8y – 6 = 18, so y = 3. So B = 3 x 3 – 3 = 6. Check: A = 5 x 3 – 3 = 12, and A + B = 12 + 6 = 18, confirming the answer. So Sophie’s present age is 6.
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Q15. The average of the ages of Karan and Sophie is 14 years. If the respective ratio of their ages 4 years from now is 7:2, what is Sophie’s present age (the smaller ratio value)?
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Answer: B
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 14, so A + B = 2 x 14 = 28. Fact 2: 4 years from now, their ages are in the ratio 7:2. So let their future ages be 7y and 2y, for some number y. Fact 3: present age plus 4 equals future age, so A = 7y – 4 and B = 2y – 4. Substituting into fact 1: (7y – 4) + (2y – 4) = 28. This simplifies to 9y – 8 = 28, so y = 4. So B = 2 x 4 – 4 = 4. Check: A = 7 x 4 – 4 = 24, and A + B = 24 + 4 = 28, confirming the answer. So Sophie’s present age is 4.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q16. The average of the ages of Karan and Sophie is 24 years. If the respective ratio of their ages 5 years from now is 47:11, what is Sophie’s present age (the smaller ratio value)?
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Answer: C
Let A = Karan’s present age, B = Sophie’s present age. Fact 1: their average age is 24, so A + B = 2 x 24 = 48. Fact 2: 5 years from now, their ages are in the ratio 47:11. So let their future ages be 47y and 11y, for some number y. Fact 3: present age plus 5 equals future age, so A = 47y – 5 and B = 11y – 5. Substituting into fact 1: (47y – 5) + (11y – 5) = 48. This simplifies to 58y – 10 = 48, so y = 1. So B = 11 x 1 – 5 = 6. Check: A = 47 x 1 – 5 = 42, and A + B = 42 + 6 = 48, confirming the answer. So Sophie’s present age is 6.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q17. The sum of the ages of Anita, Rohan, and Divya is 109 years. If Anita is 12 years younger than Divya, and the total of Rohan and Divya’s ages is 77 years, what is Rohan’s age?
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Answer: A
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 109. Fact 2: A is 12 years younger than D, so A – D = -12. Fact 3: R + D = 77. From facts 1 and 3: A = 109 – 77 = 32. From fact 2: D = A – -12 = 32 – -12 = 44. From fact 3: R = 77 – D = 77 – 44 = 33. Check: A + R + D = 32 + 33 + 44 = 109, confirming the answer. So Rohan’s age is 33.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q18. The sum of the ages of Anita, Rohan, and Divya is 74 years. If Anita is 9 years younger than Divya, and the total of Rohan and Divya’s ages is 59 years, what is Rohan’s age?
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Answer: D
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 74. Fact 2: A is 9 years younger than D, so A – D = -9. Fact 3: R + D = 59. From facts 1 and 3: A = 74 – 59 = 15. From fact 2: D = A – -9 = 15 – -9 = 24. From fact 3: R = 59 – D = 59 – 24 = 35. Check: A + R + D = 15 + 35 + 24 = 74, confirming the answer. So Rohan’s age is 35.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q19. The sum of the ages of Anita, Rohan, and Divya is 114 years. If Anita is 14 years younger than Divya, and the total of Rohan and Divya’s ages is 83 years, what is Rohan’s age?
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Answer: B
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 114. Fact 2: A is 14 years younger than D, so A – D = -14. Fact 3: R + D = 83. From facts 1 and 3: A = 114 – 83 = 31. From fact 2: D = A – -14 = 31 – -14 = 45. From fact 3: R = 83 – D = 83 – 45 = 38. Check: A + R + D = 31 + 38 + 45 = 114, confirming the answer. So Rohan’s age is 38.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q20. The sum of the ages of Anita, Rohan, and Divya is 86 years. If Anita is 16 years younger than Divya, and the total of Rohan and Divya’s ages is 68 years, what is Rohan’s age?
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Answer: C
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 86. Fact 2: A is 16 years younger than D, so A – D = -16. Fact 3: R + D = 68. From facts 1 and 3: A = 86 – 68 = 18. From fact 2: D = A – -16 = 18 – -16 = 34. From fact 3: R = 68 – D = 68 – 34 = 34. Check: A + R + D = 18 + 34 + 34 = 86, confirming the answer. So Rohan’s age is 34.
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Q21. The sum of the ages of Anita, Rohan, and Divya is 102 years. If Anita is 10 years older than Divya, and the total of Rohan and Divya’s ages is 60 years, what is Rohan’s age?
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Answer: D
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 102. Fact 2: A is 10 years older than D, so A – D = 10. Fact 3: R + D = 60. From facts 1 and 3: A = 102 – 60 = 42. From fact 2: D = A – 10 = 42 – 10 = 32. From fact 3: R = 60 – D = 60 – 32 = 28. Check: A + R + D = 42 + 28 + 32 = 102, confirming the answer. So Rohan’s age is 28.
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Q22. The sum of the ages of Anita, Rohan, and Divya is 76 years. If Anita is 5 years older than Divya, and the total of Rohan and Divya’s ages is 51 years, what is Rohan’s age?
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Answer: B
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 76. Fact 2: A is 5 years older than D, so A – D = 5. Fact 3: R + D = 51. From facts 1 and 3: A = 76 – 51 = 25. From fact 2: D = A – 5 = 25 – 5 = 20. From fact 3: R = 51 – D = 51 – 20 = 31. Check: A + R + D = 25 + 31 + 20 = 76, confirming the answer. So Rohan’s age is 31.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q23. The sum of the ages of Anita, Rohan, and Divya is 103 years. If Anita is 23 years older than Divya, and the total of Rohan and Divya’s ages is 60 years, what is Rohan’s age?
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Answer: C
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 103. Fact 2: A is 23 years older than D, so A – D = 23. Fact 3: R + D = 60. From facts 1 and 3: A = 103 – 60 = 43. From fact 2: D = A – 23 = 43 – 23 = 20. From fact 3: R = 60 – D = 60 – 20 = 40. Check: A + R + D = 43 + 40 + 20 = 103, confirming the answer. So Rohan’s age is 40.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q24. The sum of the ages of Anita, Rohan, and Divya is 76 years. If Anita is 26 years younger than Divya, and the total of Rohan and Divya’s ages is 59 years, what is Rohan’s age?
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Answer: B
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 76. Fact 2: A is 26 years younger than D, so A – D = -26. Fact 3: R + D = 59. From facts 1 and 3: A = 76 – 59 = 17. From fact 2: D = A – -26 = 17 – -26 = 43. From fact 3: R = 59 – D = 59 – 43 = 16. Check: A + R + D = 17 + 16 + 43 = 76, confirming the answer. So Rohan’s age is 16.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples
Q25. The sum of the ages of Anita, Rohan, and Divya is 98 years. If Anita is 6 years older than Divya, and the total of Rohan and Divya’s ages is 59 years, what is Rohan’s age?
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Answer: D
Let A = Anita’s age, R = Rohan’s age, D = Divya’s age. We are given three facts. Fact 1: A + R + D = 98. Fact 2: A is 6 years older than D, so A – D = 6. Fact 3: R + D = 59. From facts 1 and 3: A = 98 – 59 = 39. From fact 2: D = A – 6 = 39 – 6 = 33. From fact 3: R = 59 – D = 59 – 33 = 26. Check: A + R + D = 39 + 26 + 33 = 98, confirming the answer. So Rohan’s age is 26.
Related topics: Problems on Ages: Formulas, Shortcuts and Solved Examples