Area questions ask how much surface a shape covers, or what it costs to cover or fence it.
Read the Article: Area: Formulas, Shortcuts and Solved Examples →
0 / 25 correct · click an option to check it · +0 pts today
Q1. Find the area of an equilateral triangle with side 48 cm.
Show answer and explanation
Answer: D
Let side = a = 48 cm. Area of an equilateral triangle = (sqrt(3)/4) x a^2. a^2 = 48^2 = 2304. So area = (sqrt(3)/4) x 2304 = 576√3 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q2. Find the area of an equilateral triangle with side 60 cm.
Show answer and explanation
Answer: B
Let side = a = 60 cm. Area of an equilateral triangle = (sqrt(3)/4) x a^2. a^2 = 60^2 = 3600. So area = (sqrt(3)/4) x 3600 = 900√3 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q3. Find the area of an equilateral triangle with side 22 cm.
Show answer and explanation
Answer: A
Let side = a = 22 cm. Area of an equilateral triangle = (sqrt(3)/4) x a^2. a^2 = 22^2 = 484. So area = (sqrt(3)/4) x 484 = 121√3 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q4. Find the area of an equilateral triangle with side 54 cm.
Show answer and explanation
Answer: C
Let side = a = 54 cm. Area of an equilateral triangle = (sqrt(3)/4) x a^2. a^2 = 54^2 = 2916. So area = (sqrt(3)/4) x 2916 = 729√3 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q5. Find the area of an equilateral triangle with side 4 cm.
Show answer and explanation
Answer: D
Let side = a = 4 cm. Area of an equilateral triangle = (sqrt(3)/4) x a^2. a^2 = 4^2 = 16. So area = (sqrt(3)/4) x 16 = 4√3 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q6. Find the area of an equilateral triangle with side 6 cm.
Show answer and explanation
Answer: C
Let side = a = 6 cm. Area of an equilateral triangle = (sqrt(3)/4) x a^2. a^2 = 6^2 = 36. So area = (sqrt(3)/4) x 36 = 9√3 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q7. Find the area of a triangle whose sides measure 20 cm, 20 cm, and 24 cm.
Show answer and explanation
Answer: B
Let the sides be a = 20 cm, b = 20 cm, c = 24 cm. Semi-perimeter s = (a+b+c)/2 = (20+20+24)/2 = 32. s-a = 12, s-b = 12, s-c = 8. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 32 x 12 x 12 x 8 = 36864. Area = sqrt(36864) = 192 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q8. Find the area of a triangle whose sides measure 18 cm, 24 cm, and 30 cm.
Show answer and explanation
Answer: A
Let the sides be a = 18 cm, b = 24 cm, c = 30 cm. Semi-perimeter s = (a+b+c)/2 = (18+24+30)/2 = 36. s-a = 18, s-b = 12, s-c = 6. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 36 x 18 x 12 x 6 = 46656. Area = sqrt(46656) = 216 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q9. Find the area of a triangle whose sides measure 20 cm, 26 cm, and 26 cm.
Show answer and explanation
Answer: B
Let the sides be a = 20 cm, b = 26 cm, c = 26 cm. Semi-perimeter s = (a+b+c)/2 = (20+26+26)/2 = 36. s-a = 16, s-b = 10, s-c = 10. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 36 x 16 x 10 x 10 = 57600. Area = sqrt(57600) = 240 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q10. Find the area of a triangle whose sides measure 9 cm, 10 cm, and 17 cm.
Show answer and explanation
Answer: C
Let the sides be a = 9 cm, b = 10 cm, c = 17 cm. Semi-perimeter s = (a+b+c)/2 = (9+10+17)/2 = 18. s-a = 9, s-b = 8, s-c = 1. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 18 x 9 x 8 x 1 = 1296. Area = sqrt(1296) = 36 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q11. Find the area of a triangle whose sides measure 13 cm, 14 cm, and 15 cm.
Show answer and explanation
Answer: A
Let the sides be a = 13 cm, b = 14 cm, c = 15 cm. Semi-perimeter s = (a+b+c)/2 = (13+14+15)/2 = 21. s-a = 8, s-b = 7, s-c = 6. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 21 x 8 x 7 x 6 = 7056. Area = sqrt(7056) = 84 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q12. Find the area of a triangle whose sides measure 3 cm, 4 cm, and 5 cm.
Show answer and explanation
Answer: D
Let the sides be a = 3 cm, b = 4 cm, c = 5 cm. Semi-perimeter s = (a+b+c)/2 = (3+4+5)/2 = 6. s-a = 3, s-b = 2, s-c = 1. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 6 x 3 x 2 x 1 = 36. Area = sqrt(36) = 6 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q13. Find the area of a triangle whose sides measure 10 cm, 24 cm, and 26 cm.
Show answer and explanation
Answer: C
Let the sides be a = 10 cm, b = 24 cm, c = 26 cm. Semi-perimeter s = (a+b+c)/2 = (10+24+26)/2 = 30. s-a = 20, s-b = 6, s-c = 4. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 30 x 20 x 6 x 4 = 14400. Area = sqrt(14400) = 120 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q14. Find the area of a triangle whose sides measure 6 cm, 50 cm, and 52 cm.
Show answer and explanation
Answer: B
Let the sides be a = 6 cm, b = 50 cm, c = 52 cm. Semi-perimeter s = (a+b+c)/2 = (6+50+52)/2 = 54. s-a = 48, s-b = 4, s-c = 2. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 54 x 48 x 4 x 2 = 20736. Area = sqrt(20736) = 144 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q15. Find the area of a triangle whose sides measure 5 cm, 12 cm, and 13 cm.
Show answer and explanation
Answer: A
Let the sides be a = 5 cm, b = 12 cm, c = 13 cm. Semi-perimeter s = (a+b+c)/2 = (5+12+13)/2 = 15. s-a = 10, s-b = 3, s-c = 2. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 15 x 10 x 3 x 2 = 900. Area = sqrt(900) = 30 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q16. Find the area of a triangle whose sides measure 6 cm, 8 cm, and 10 cm.
Show answer and explanation
Answer: D
Let the sides be a = 6 cm, b = 8 cm, c = 10 cm. Semi-perimeter s = (a+b+c)/2 = (6+8+10)/2 = 12. s-a = 6, s-b = 4, s-c = 2. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 12 x 6 x 4 x 2 = 576. Area = sqrt(576) = 24 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q17. Find the area of a triangle whose sides measure 9 cm, 12 cm, and 15 cm.
Show answer and explanation
Answer: C
Let the sides be a = 9 cm, b = 12 cm, c = 15 cm. Semi-perimeter s = (a+b+c)/2 = (9+12+15)/2 = 18. s-a = 9, s-b = 6, s-c = 3. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 18 x 9 x 6 x 3 = 2916. Area = sqrt(2916) = 54 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q18. Find the area of a triangle whose sides measure 18 cm, 20 cm, and 34 cm.
Show answer and explanation
Answer: B
Let the sides be a = 18 cm, b = 20 cm, c = 34 cm. Semi-perimeter s = (a+b+c)/2 = (18+20+34)/2 = 36. s-a = 18, s-b = 16, s-c = 2. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 36 x 18 x 16 x 2 = 20736. Area = sqrt(20736) = 144 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q19. Find the area of a triangle whose sides measure 5 cm, 5 cm, and 6 cm.
Show answer and explanation
Answer: D
Let the sides be a = 5 cm, b = 5 cm, c = 6 cm. Semi-perimeter s = (a+b+c)/2 = (5+5+6)/2 = 8. s-a = 3, s-b = 3, s-c = 2. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 8 x 3 x 3 x 2 = 144. Area = sqrt(144) = 12 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q20. Find the area of a triangle whose sides measure 12 cm, 16 cm, and 20 cm.
Show answer and explanation
Answer: A
Let the sides be a = 12 cm, b = 16 cm, c = 20 cm. Semi-perimeter s = (a+b+c)/2 = (12+16+20)/2 = 24. s-a = 12, s-b = 8, s-c = 4. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 24 x 12 x 8 x 4 = 9216. Area = sqrt(9216) = 96 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q21. Find the area of a triangle whose sides measure 5 cm, 5 cm, and 8 cm.
Show answer and explanation
Answer: B
Let the sides be a = 5 cm, b = 5 cm, c = 8 cm. Semi-perimeter s = (a+b+c)/2 = (5+5+8)/2 = 9. s-a = 4, s-b = 4, s-c = 1. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 9 x 4 x 4 x 1 = 144. Area = sqrt(144) = 12 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q22. Find the area of a triangle whose sides measure 10 cm, 10 cm, and 12 cm.
Show answer and explanation
Answer: A
Let the sides be a = 10 cm, b = 10 cm, c = 12 cm. Semi-perimeter s = (a+b+c)/2 = (10+10+12)/2 = 16. s-a = 6, s-b = 6, s-c = 4. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 16 x 6 x 6 x 4 = 2304. Area = sqrt(2304) = 48 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q23. Find the area of a triangle whose sides measure 10 cm, 10 cm, and 16 cm.
Show answer and explanation
Answer: C
Let the sides be a = 10 cm, b = 10 cm, c = 16 cm. Semi-perimeter s = (a+b+c)/2 = (10+10+16)/2 = 18. s-a = 8, s-b = 8, s-c = 2. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 18 x 8 x 8 x 2 = 2304. Area = sqrt(2304) = 48 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q24. Find the area of a triangle whose sides measure 10 cm, 13 cm, and 13 cm.
Show answer and explanation
Answer: D
Let the sides be a = 10 cm, b = 13 cm, c = 13 cm. Semi-perimeter s = (a+b+c)/2 = (10+13+13)/2 = 18. s-a = 8, s-b = 5, s-c = 5. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 18 x 8 x 5 x 5 = 3600. Area = sqrt(3600) = 60 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples
Q25. Find the area of a triangle whose sides measure 3 cm, 25 cm, and 26 cm.
Show answer and explanation
Answer: A
Let the sides be a = 3 cm, b = 25 cm, c = 26 cm. Semi-perimeter s = (a+b+c)/2 = (3+25+26)/2 = 27. s-a = 24, s-b = 2, s-c = 1. Heron’s formula: Area = sqrt[s(s-a)(s-b)(s-c)]. Product under the root = 27 x 24 x 2 x 1 = 1296. Area = sqrt(1296) = 36 sq cm.
Related topics: Area: Formulas, Shortcuts and Solved Examples