If the temperature difference between a liquid and its surroundings is doubled, what happens to its rate of heat loss, per Newton’s Law of Cooling?

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1. If the temperature difference between a liquid and its surroundings is doubled, what happens to its rate of heat loss, per Newton’s Law of Cooling?

It stays the same

It roughly doubles

It roughly triples

It roughly quadruples

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Newton’s Law of Cooling states that the rate of heat loss is directly proportional to the temperature difference, so doubling that difference roughly doubles the cooling rate.