This lesson gives each rule with the reason it works. It solves five examples step by step and lists the traps that cost marks.
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Q1. A number has 14 added to it, the sum is multiplied by 3, the product is divided by 2, and then 5 is subtracted, leaving 52. What was the original number?
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Answer: A
Let the original number be x. Following the operations: x + 14 = step1, step1 x 3 = step2, step2 / 2 = step3, step3 – 5 = 52. Working backward from the result 52: step3 = 52 + 5 = 57. step2 = step3 x 2 = 57 x 2 = 114. step1 = step2 / 3 = 114/3 = 38. x = step1 – 14 = 38 – 14 = 24. Check: with x=24, ((24+14) x 3)/2 – 5 = (38 x 3)/2 – 5 = 114/2 – 5 = 57 – 5 = 52, which matches.
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Q2. Four consecutive even numbers sum to 292. What is the sum of the very next set of four consecutive even numbers?
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Answer: B
The first set is 70, 72, 74, 76, summing to 292. The next set shifts every number forward by 8 (four steps of 2 each), so each of the 4 numbers increases by 8. Total increase = 4 x 8 = 32. New sum = 292 + 32 = 324. Check: the next set is 78, 80, 82, 84, which sums to 324.
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Q3. Four consecutive numbers sum to 166. What is the sum of the very next set of four consecutive numbers?
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Answer: C
The first set is 40, 41, 42, 43, summing to 166. The next set shifts every number forward by 4 (four steps of 1 each), so each of the 4 numbers increases by 4. Total increase = 4 x 4 = 16. New sum = 166 + 16 = 182. Check: the next set is 44, 45, 46, 47, which sums to 182.
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Q4. Four consecutive even numbers sum to 76. What is the sum of the very next set of four consecutive even numbers?
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Answer: D
The first set is 16, 18, 20, 22, summing to 76. The next set shifts every number forward by 8 (four steps of 2 each), so each of the 4 numbers increases by 8. Total increase = 4 x 8 = 32. New sum = 76 + 32 = 108. Check: the next set is 24, 26, 28, 30, which sums to 108.
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Q5. Four consecutive even numbers sum to 212. What is the sum of the very next set of four consecutive even numbers?
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Answer: A
The first set is 50, 52, 54, 56, summing to 212. The next set shifts every number forward by 8 (four steps of 2 each), so each of the 4 numbers increases by 8. Total increase = 4 x 8 = 32. New sum = 212 + 32 = 244. Check: the next set is 58, 60, 62, 64, which sums to 244.
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Q6. Four consecutive numbers sum to 90. What is the sum of the very next set of four consecutive numbers?
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Answer: B
The first set is 21, 22, 23, 24, summing to 90. The next set shifts every number forward by 4 (four steps of 1 each), so each of the 4 numbers increases by 4. Total increase = 4 x 4 = 16. New sum = 90 + 16 = 106. Check: the next set is 25, 26, 27, 28, which sums to 106.
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Q7. Four consecutive even numbers sum to 60. What is the sum of the very next set of four consecutive even numbers?
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Answer: C
The first set is 12, 14, 16, 18, summing to 60. The next set shifts every number forward by 8 (four steps of 2 each), so each of the 4 numbers increases by 8. Total increase = 4 x 8 = 32. New sum = 60 + 32 = 92. Check: the next set is 20, 22, 24, 26, which sums to 92.
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Q8. Four consecutive odd numbers sum to 264. What is the sum of the very next set of four consecutive odd numbers?
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Answer: A
The first set is 63, 65, 67, 69, summing to 264. The next set shifts every number forward by 8 (four steps of 2 each), so each of the 4 numbers increases by 8. Total increase = 4 x 8 = 32. New sum = 264 + 32 = 296. Check: the next set is 71, 73, 75, 77, which sums to 296.
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Q9. Four consecutive numbers sum to 174. What is the sum of the very next set of four consecutive numbers?
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Answer: D
The first set is 42, 43, 44, 45, summing to 174. The next set shifts every number forward by 4 (four steps of 1 each), so each of the 4 numbers increases by 4. Total increase = 4 x 4 = 16. New sum = 174 + 16 = 190. Check: the next set is 46, 47, 48, 49, which sums to 190.
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Q10. How many prime numbers are there between 200 and 240?
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Answer: C
We need primes p with 200 <= p <= 240, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 211, 223, 227, 229, 233, 239. Counting these gives 6 primes. So the answer is 6.
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Q11. How many prime numbers are there between 50 and 80?
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Answer: B
We need primes p with 50 <= p <= 80, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 53, 59, 61, 67, 71, 73, 79. Counting these gives 7 primes. So the answer is 7.
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Q12. How many prime numbers are there between 160 and 200?
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Answer: A
We need primes p with 160 <= p <= 200, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 163, 167, 173, 179, 181, 191, 193, 197, 199. Counting these gives 9 primes. So the answer is 9.
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Q13. How many prime numbers are there between 130 and 170?
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Answer: D
We need primes p with 130 <= p <= 170, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 131, 137, 139, 149, 151, 157, 163, 167. Counting these gives 8 primes. So the answer is 8.
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Q14. How many prime numbers are there between 250 and 290?
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Answer: A
We need primes p with 250 <= p <= 290, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 251, 257, 263, 269, 271, 277, 281, 283. Counting these gives 8 primes. So the answer is 8.
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Q15. How many prime numbers are there between 130 and 180?
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Answer: B
We need primes p with 130 <= p <= 180, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 131, 137, 139, 149, 151, 157, 163, 167, 173, 179. Counting these gives 10 primes. So the answer is 10.
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Q16. How many prime numbers are there between 250 and 300?
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Answer: D
We need primes p with 250 <= p <= 300, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 251, 257, 263, 269, 271, 277, 281, 283, 293. Counting these gives 9 primes. So the answer is 9.
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Q17. How many prime numbers are there between 160 and 210?
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Answer: C
We need primes p with 160 <= p <= 210, where a prime has no divisors other than 1 and itself. Checking each integer in this range: the primes are 163, 167, 173, 179, 181, 191, 193, 197, 199. Counting these gives 9 primes. So the answer is 9.
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Q18. How many perfect squares are there strictly between 345 and 527?
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Answer: D
We need perfect squares strictly between 345 and 527. Checking each integer’s square in that range: 361, 400, 441, 484 all fall strictly between 345 and 527. Counting these gives 4 perfect squares. So the count is 4.
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Q19. What is the sum of all perfect squares strictly between 305 and 529?
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Answer: B
We need perfect squares strictly between 305 and 529. Checking each integer’s square in that range: 324, 361, 400, 441, 484 all fall strictly between 305 and 529. Adding them: 324 + 361 + 400 + 441 + 484 = 2010. So the sum is 2010.
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Q20. What is the sum of all perfect squares strictly between 433 and 662?
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Answer: C
We need perfect squares strictly between 433 and 662. Checking each integer’s square in that range: 441, 484, 529, 576, 625 all fall strictly between 433 and 662. Adding them: 441 + 484 + 529 + 576 + 625 = 2655. So the sum is 2655.
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Q21. What is the sum of all perfect squares strictly between 98 and 443?
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Answer: A
We need perfect squares strictly between 98 and 443. Checking each integer’s square in that range: 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400, 441 all fall strictly between 98 and 443. Adding them: 100 + 121 + 144 + 169 + 196 + 225 + 256 + 289 + 324 + 361 + 400 + 441 = 3026. So the sum is 3026.
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Q22. How many perfect squares are there strictly between 60 and 243?
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Answer: C
We need perfect squares strictly between 60 and 243. Checking each integer’s square in that range: 64, 81, 100, 121, 144, 169, 196, 225 all fall strictly between 60 and 243. Counting these gives 8 perfect squares. So the count is 8.
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Q23. What is the sum of all perfect squares strictly between 191 and 486?
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Answer: D
We need perfect squares strictly between 191 and 486. Checking each integer’s square in that range: 196, 225, 256, 289, 324, 361, 400, 441, 484 all fall strictly between 191 and 486. Adding them: 196 + 225 + 256 + 289 + 324 + 361 + 400 + 441 + 484 = 2976. So the sum is 2976.
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Q24. How many perfect squares are there strictly between 79 and 263?
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Answer: A
We need perfect squares strictly between 79 and 263. Checking each integer’s square in that range: 81, 100, 121, 144, 169, 196, 225, 256 all fall strictly between 79 and 263. Counting these gives 8 perfect squares. So the count is 8.
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Q25. What is the sum of all perfect squares strictly between 180 and 372?
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Answer: B
We need perfect squares strictly between 180 and 372. Checking each integer’s square in that range: 196, 225, 256, 289, 324, 361 all fall strictly between 180 and 372. Adding them: 196 + 225 + 256 + 289 + 324 + 361 = 1651. So the sum is 1651.
Related topics: Number System: Formulas, Shortcuts and Solved Examples
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